Based on the data collected, explain why a launch angle of 30 degrees (high horizontal velocity & small time of flight) will allow a projectile to go just as far when the launch angle of 60 degrees (low horizontal velocity and large time of flight).

Explanation:

The horizontal distance traveled by the projectile is given by the formula

The formula for the time of flight is given by

Case I: when the launch angle is 30°

So,

Horizontal velocity = u Cos 30 = 0.866 u

Case II: when the launch angle is 60°

Horizontal velocity = u Cos 60 = 0.5 u

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

grav forces affect all objects magnetic forces affect magnetic objects and electric currents