Based on the data collected, explain why a launch angle of 30 degrees (high horizontal velocity & small time of flight) will allow a projectile to go just as far when the launch angle of 60 degrees (low horizontal velocity and large time of flight).

Explanation:

The horizontal distance traveled by the projectile is given by the formula

The formula for the time of flight is given by

Case I: when the launch angle is 30°

So,

Horizontal velocity = u Cos 30 = 0.866 u

Case II: when the launch angle is 60°

Horizontal velocity = u Cos 60 = 0.5 u

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

not too sure thinking all accelerations are pointed down