What is an object's final velocity if it has an initial velocity of +12
meters/second with a constant acceleration of +14
meters/second and has traveled 48 meters in the +x direction?

v = 38.57 m/s

Explanation:

Given that,

The initial velocity of the object in x direction, u = 12 m/s

The acceleration of the object in x direction, a = 14 m/s²

The distance traveled by the object in x direction, s = 48 m

The equations of motion of a moving body with initial velocity and acceleration is given by the formula

                                      v² = u² + 2as

Substituting the values in the above equation

                                      v² = (12 m/s)² + 2 x 14 m/s² x 48 m

                                           = 1488

Therefore,                      

                                        v = 38.57 m/s

Hence, the final velocity of the body, v = 38.57 m/s

b would be the answer

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.