Aperson is pulling their 20 kg luggage using the luggage handle. the handle is at an angle of 56 degrees above the horizontal. if the person is pulling with a force of 71 n, what is the horizontal acceleration of the luggage (ignore all friction)
3.19 m/s^2
1.99 m/s^2
0.74 m/s^2
1.02 m/s^2

The answer to your question is:  a = 1.99 m/s²

Explanation:

Data

mass = 20 kg

angle = 56°

Force = 71 N

horizontal acceleration = ?

Process

Find the horizontal force

                                           cos Ф = adjacent side / hypotenuse

                                          adjacent side = hypotenuse x cosФ

                                          adjacent side = 71 x cos 56

                                          a.s. = 39.70 N

Newton's second law

                                  F = ma

                                  a = F/m

                                 a = 39.7 / 20

                                  a = 1.99 m/s²

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