Km
two buses leave a station at the same time and travel in opposite directions. one bus travels 10 - - slower than the other. if the two buses are 1442
kilometers apart after 7 hours, what is the rate of each bus?
rate of the slower bus:
x
5
?
rate of the faster bus:

The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  .

Step-by-step explanation:

Given as :

The two buses apart 1442 km

The time taken for apart = 7 hours

Let The speed of faster bus = x kmph

The speed of slower bus = ( x - 10 ) kmph

Now Speed =

∵ Both the buses traveling in opposite direction

So, The speed of faster bus + the speed of slower bus =  

Or, x + x - 10 =

or, 2 x = 206 + 10

or, 2 x = 216

∴  x =

I.e x = 108  kmph

So, The speed of faster bus = x = 108 kmph

And The speed of slower bus = ( x - 10 ) = 108 - 10 = 98 kmph

Hence The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  . Answer

im with everythinglos so yeahhhhh

step-by-step explanation:

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.