Joe pushes down the length of the handle of a 10.9 kg lawn spreader. the handle makes an angle of 45.3 ◦ with the horizontal. joe wishes to accelerate the spreader from rest to 1.35 m/s in 1.6 s. what force must joe apply to the handle? answer in units of n

F = 13.08 N

Explanation:

given,

mass of spreader = 10.9 Kg

angle made with angle = 45.3°

accelerate the spreader to 1.35 m/s in 1.6 s.

Acceleration =

                      =

                      = 0.844 m/s²

momentum in = momentum out

F × t = m  × v

F×1.125 = 14.175

F = 13.08 N

hence, the force applied by the joe is equal to F = 13.08 N