Afirecracker breaks up into several pieces, one of which has a mass of 200 g and flies off along
the x-axis with a speed of 82.0 m/s. a second piece has a mass of 300 g and flies off along the
y-axis with a speed of 45.0 m/s. what are the magnitude and direction of the total momentum
of these two pieces?
1) 361 kg m/s at 56.3 from the x-axis
2) 93.5 kg m/s at 28.8 from the x-axis
3) 21.2 kg m/s at 39.5 from the x-axis
4) 361 kg m/s at 0.983 from the x-axis
5) 21.2 kg m/s at 56.3 from the x-axis

Explanation:

It is given that,

Mass of first piece,

Speed of first piece,

Mass of second piece,

Speed of first piece,

The momentum along x axis is given by :

The momentum along y axis is given by :

Let p is the total momentum of these two pieces. Its magnitude is given by :

p = 21.24 kg-m/s

The direction of total momentum is given by :

So, the magnitude and direction of the total momentum  of these two pieces are 21.2 kg m/s at 39.5 from the x-axis. Hence, this is the required solution.

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.