Afireworks shell is accelerated from rest to a velocity of 50.0 m/s over a distance of 0.240 m. (a) how long (in s) did the acceleration last? s (b) calculate the acceleration in m/s^2). (enter the magnitude.) /s^2

0.0096 seconds

5208.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The acceleration of the firework shell was 5208.33 m/s²

The acceleration lasted for 0.0096 seconds

(a) 0.0096 sec

(b)

Explanation:

We have given that firewall shell starts from rest so initial velocity u = 0 m/sec

And final velocity v = 50 m/sec

Distance s = 0.240 m

(A) From first equation pf motion we know that v = u+at

So 50 = 0+at

at = 50

Now from second equation of motion

Using the value of at = 50

(b) As at = 50

So

none, its a machine

hypothesising or postulating