2. an airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind
from west to east, as represented in the diagram below.
what is the resultant speed of the plane?
(1) 170. m/s
(2) 214 m/s
(3) 226 m/s
(4) 270. m/s
220. m/s
50.0 m/s

The resultant of the speed of the plane is 226 m/s.

The given parameters;

The resultant of the speed of the plane is calculated by applying Pythagoras theorem as shown below;

R = 220² + 50²

R = 50900

R = √50900

R = 225.61 m/s

R ≈ 226 m/s.

Thus, the resultant of the speed of the plane is 226 m/s.

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The resultant speed of the plane  is (3) 226 m/s

Why?

We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

Hence, we have that the resultant speed of the plane  is (3) 226 m/s

Have a nice day!