There is a storage tank that is pumping water; the water temperature is 200 f and the rate at which the water is pumped is 50 gal/min. the pump has a motor (work is supplied at the rate of 2hp). the water then flows into a heat exchanger (giving up heat at the rate of 40,000 btu/min), the water then reaches a storage tank (elevation 50 ft above the first tank). what is the temperature of the water delivered to the second tank?

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The relationship of both of them

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.