What is the total distance traveled by the car
during this 6.0-second interval?
(1) 10. m
(3) 40. m
(2) 20. m
(4) 60. m

*Graph is attached with the answer*

Total distance traveled by the car is 40 m

Explanation:

It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity

So, we solved this question in 2 parts

Part 1:

               initial velocity = v₁ = 0 m/s

               final velocity = v₂ = 10 m/s

                time = t = 4 s

                acceleration = a = (v₂ - v₁)/t

                                a = 10/4 = 2.5 m/s²

Using 3rd equation of motion

                2as = v₂² - v₁²

                 2(2.5)s = 10²

                      s₁ = 100/5

                     s₁ = 20 m

Part 2:

            s₂ = v₂t

            s₂ = 10 × 2

            s₂ = 20 m

Total distance = S = s₁ + s₂

                              = 20 + 20

                          S = 40 m

490 n

f=125n a=2.5m/s2