Apackage is dropped from a helicopter falling at 36 m/s.
if it takes 11.0s before the package strikes the ground, how high above the ground was the package when it was released? ignore air resistance

The height above the ground is 988.9 meters.

Explanation:

It is given that,

Initial speed of the package, u = 36 m/s

Time taken by the package to reach the ground, t = 11 s

Let h is the height above the ground when it was released. It can be calculated using the second equation of motion as :

a = g

h = 988.9 meters

So, the height above the ground is 988.9 meters. Hence, this is the required solution.