Acentrifuge in a medical laboratory rotates at an
angularspeed of 3800 rev/min. when switched off, it rotates through
46.0revolutions before coming to rest. find the constant
angularacceleration of the centrifuge.

- 273.77 rad/s^2

Explanation:

fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps

f = 0

ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s

ω = 2 π f = 0

θ = 46 revolutions = 46 x 2π radian = 288.88 radian

Let α be the angular acceleration of the centrifuge

Use third equation of motion for rotational motion

α = - 273.77 rad/s^2

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explanation:

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