Physics, 14.09.2019 03:30 5theth

If the wavelength of an electron is 4.63 x 10^−7 m, how fast is it moving?

Answers: 2

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Answers

Answer from: kwilson5328

it move with velocity 1571 m/s

Explanation:

given data

wavelength λ = 4.63 × $10^{-7}$ m

to find out

how fast is it moving

solution

we will use here de Broglie wavelength equation

that is

wavelength λ = $\frac{h}{mv}$ ..........1

here h is planck constant = 6.626068 × $10^{-34}$

and m is mass of electron i.e = 9.10938188 × $10^{-31}$

and v is velocity

put all value we find velocity in equation 1

wavelength λ = $\frac{h}{mv}$

v = $\frac{6.626068*10^{-34}}{9.10938188*10^{-31}*4.63*10^{-7}}$

v = 1571.035464

so it move with velocity 1571 m/s

Answer from: vannybelly83

$v=1.57*10^{3}\frac{m}{s}$

Explanation:

As DeBroglie equation proved by Davisson-Germer experiment says, the wavelength of an electron is related with its velocity with the equation:

λ = $\frac{h}{mv}$

where m is the mass of the electron $m=9.11*10^{-31}kg$ , h is the Planck´s constant $h=6.626*10^{-34}J.s$ and v its velocity.

Solving the equation for the velocity of the electron, we have:

v = h/mλ

And replacing the values:

$v=\frac{6.626*10^{-34}J.s}{(9.11*10^{-31}Kg)*(4.63*10^{-7}m)}$

$v=1570.9\frac{m}{s}$

$v=1.57*10^{3}\frac{m}{s}$

Answer from: Quest

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

time (seconds)

answer: 0 meters/second^2

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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