Joshua spins a spinner twice. The spinner consists of 3 equally spaced colors, Red, Blue, and Yellow. What is the probability that the spinner will stop on green and then yellow? ASAP

Step-by-step explanation:

Given a spinner with 3 equally spaced colors Red, Blue, Yellow.

The colors are equally spaced, therefore probability of each color must be same.

i.e. Probability of occurrence of any one color in one spin is .

To find:

Probability that spinner will stop one green in first spin and yellow in the second spin = ?

Solution:

As all the colors are equally likely to occur, so

Probability of green color in the first spin, P(G) =

Probability of yellow color in the second spin, P(Y) =

As we can observe that occurrence of any color in the second round of spin is not dependent on the color occurrence in the first spin, therefore these are the independent events.

P(G and Y) = P(G) P(Y)

Therefore, the required probability is

.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !