You blow across the open mouth of an empty test tube and produce the fundamental standing wave of the air column inside the test tube. the speed of sound in air is 344 m/s and the test tube acts as a stopped pipe. a) if the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave? b) what is the frequency of the fundamental standing wave in the air column if the test tube is half-filled with water?

The particles of the gas inside the ball heats up, bouncing off each other and spreading farther apart.hope my answer has you : )

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

It maybe because uranus is made of gas but uranus has a solid core in the middle

Chromium  +  hydrogen sulfate  =  chromium(iii) sulfate  +  hydrogenso then it will be  a. cr + h2so4? cr2(so4)3 + h2