Abus travels 4 km due north and then 3 km due west going
from bus station a to bus station b. the magnitude of the bus'
displacement from station a to station b is __km

Here, we are required to find the magnitude of the bus

displacement from station A to station B.

The magnitude of the bus

displacement from station A to station B is 5km.

The magnitude of the displacement is the "distance between the starting position of a body or object and the end position of that body or object".

The bus moves 4km north and then moves 3km west, forming a right triangle. Its displacement is therefore the length of the hypotenuse.

let

x = length of the hypotenuse.

x² = 3² + 4²

x² = 9 + 16

x² = 25

Then remove the square on x by adding square roots to both sides

√x² = √25

x = √25

x = 5

The magnitude of the bus's displacement from station A to station B is 5 km.

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Explanation:

The magnitude of the displacement is the distance between the starting position and the end position.

The bus moves north, then west, forming a right triangle.  Its displacement is therefore the length of the hypotenuse.

x² = 3² + 4²

x = 5

The magnitude of the bus's displacement from station A to station B is 5 km.

(75°f − 32) × 5/9 = 23.889°c