Glycerin, with a viscosity of 1.5 n ∙ s/m 2, is flowing with an average speed of 1.2 m/s through a tube that has a radius of 5.0 mm and is 25 cm long. what is the drop in pressure over the length of this pipe

The pressure drop over the length of the pipe is 140000 kPa.

Explanation:

let R be the radius of the pipe.

let V be the volume flow rate.

let v be the average speed of the Glycerin.

let A be the area of the pipe.

then, the volume flow rate is given by:

V = v×A

V =  [π×P×r^4]/[8×Vi×L]

[π×P×r^4]/[8×Vi×L] = v×A

P = [8×Vi×L]×v×A/[π×r^4]

  = [8×Vi×L×v×π×r^2]/[π×r^4]

  = [8×Vi×L×v]/[r^2]

  = [8×1.5×(25×10^-2)×(1.2)]/[(5×10^-2)^2]

  = 140000 kPa

Therefore, the pressure drop over the length of the pipe is 140000 kPa.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015