At high noon, a sinusoidal electromagnetic wave is heading straight toward san diego. at a 12: 00 sharp, the electric field at a certain location is 700 n/c directed south. a) what is the magnitude and direction of the magnetic field at this location at this instant? b) if it takes 1.0 x 10^-15 seconds for the fields at this location to return to the values described above, what is the wavelength of this wave? c) does this wave fall within the visible range? d) at what rate does this wave deliver energy to a patch of earth of area 2 m2, assuming all is absorbed?

the higher the current the higher the mag field around it the higher the influence on the compass

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

blue light is scattered in different directions by the tiny molecules of air. blue is scattered more than other colours because it has a shorter distance to travel which results in smaller waves. this is why we see a blue sky most of the time.