An ac source has an output rms voltage of 86.0 v at a frequency of 75.0 hz. the source is connected across a 28.5-mh inductor. (a) find the inductive reactance of the circuit. (b) find the rms current in the circuit. (c) find the maximum current in the circuit.

A) The reactance of the inductor is given by:

X = 2πfL

X = reactance, f = source frequency, L = inductance

Given values:

f = 75.0Hz, L = 28.5×10⁻³H

Plug in and solve for X:

X = 2π(75.0)(28.5×10⁻³)

X = 13.4Ω

B) V = IZ

V = rms source voltage, I = rms current, Z = impedance

Given values:

V = 86.0V

With just the inductor in the circuit, Z = X = 13.4Ω

Plug in and solve for I:

86.0 = I(13.4)

I = 6.42A

C) The rms current is given by:

We have = 6.42A so plug that in and solve for :

= 9.08A

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