The armature of a 60 hz ac generator rotates in a 0.12 t b-field. if the area of the coils is 0.03 m2, how many loops must the coil contain if the peak output is to be v = 270 v? what will the current & power output (not the power loss) be if the resistance of the coil is 0.4 ? ?

Explanation:

it is given that,

Frequency of AC generator, f = 60 Hz

Magnetic field, B = 0.12 T

Area of the coil, A = 0.03 m²

Peak out put, V = 270 V

Resistance of the coil, R = 04 ohms

1. Let N is the number of loops the coil must contain. The peak voltage of AC generator is given by :

N = 199

2. Applying Ohm's law as :

I = 675 A

3. Power,

P = 182250 watts

Hence, this is the required solution.

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