Four point masses, each of mass 1.9 $kg$ are placed at the corners of a square of side 2.2 $m$. find the moment of inertia of this system about an axis that is perpendicular to the plane of the square and passes through one of the masses.

I = 36.78 kg m^{2}

Explanation:\

Given data:

side of square = 2.2 m

mass =1.9 kg

The moment of inertia i is the total sum of the moments of inertia of the 4 point masses  and it is given as

       =

I = 36.78 kg m^{2}

b) phosphorus pentoxide

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.