Travelling with velocity 1) calculate the energy e (in ev) and direction vector ω for a neutron v= 2132 +3300+154 k [m/sec]. (3 points) ^ ^

Explanation:

Given:

Velocity vector

the mass of neutron, m = 1.67 × 10⁻²⁷ kg

Now,

the kinetic energy (K.E) is given as:

or

or

substituting the values in the K.E equation

or

also

1J = 6.242 × 10¹⁸ eV

thus,

Now, the direction vector

or

or

or

not too sure thinking it will always be directed towards the centre of the earth. could be wrong not sure

what is the actual question though?