Mathematics, 12.08.2020 05:01 izzynikkie
A newspaper conducted a statewide survey concerning a proposal to raise taxes in order to prevent budget cuts to education. The newspaper took a random sample (assume it is an SRS) of 1200 registered voters and found that 580 would vote to raise taxes. Let p represent the proportion of registered voters in the state that would vote to raise taxes.
1. A 90% confidence interval for p is:
a. 0.483 ± 0.014.
b. 0.483 ± 0.024.
c. 0.483 ± 0.028.
d. 0.483 ± 0.249.
2. How large a sample n would you need to estimate p with margin of error 0.01 with 95% confidence? Use the guess p* = 0.5 as the value for p.
a. n = 49
b. n = 1500
c. n = 4800
d. n = 9604
3. Let p be the proportion of citizens in the city opposed to the ban on smoking in public places. To determine if the majority of citizens in the city oppose the ban on smoking in public places,
a. test the hypotheses H0: p = 0.50, Ha: p 0.50.
b. test the hypotheses H0: p = 0.50, Ha: p > 0.50.
c. test the hypotheses H0: p = 0.77, Ha: p > 0.77.
d. none of the above.
Answers: 3
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Idon’t understand this.. will someone ? will mark brainliest along with 20 points.
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A newspaper conducted a statewide survey concerning a proposal to raise taxes in order to prevent bu...
History, 21.07.2019 07:30