Aroom with dimensions 7.00m×8.00m×2.50m is to be filled with pure oxygen at 22.0 °c and 1.00 atm. the molar mass of oxygen is 32.0 g/mol.

how many moles n oxygen of oxygen are required to fill the room?
what is the mass m oxygen of this oxygen?

1. 5765 mol

First of all, let's calculate the volume of the room (which corresponds to the volume of the gas):

We also know the following data about the gas:

is the temperature

is the pressure

Then we can use the ideal gas law

with R being the gas constant

to find the number of moles of the gas:

2. 184.5 kg

The molar mass of oxygen is

this corresponds to the mass of 1 mol of oxygen.

In this problem, the number of moles is

n = 5765 mol

So the total mass of these n moles of oxygen will be:

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

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