Equation of a line, use the slope intercept formula for points (3,-6) and (5,8) including a check. please help me learn instead of telling me the answer :)

i’ll show u what i have so far

y=7x-27

Step-by-step explanation:

The equation of a line is given by y=mx+C where m is the gradient of the line or slope and c is the intercept on your axis. according to your question, you are given two point on (3,-6) and (5,8). so we can get the gradient m= Y2-Y1/X2-X1= gradient. so Y1= -6, Y2=8 , X1=3, X2=5

slope= 8-(-6)/5-3=14/2=7. so m=7so the equation of line can be written in form y=7x+C. but we need to find C. C can be gotten from where the line passes through (3,-6) that is when x=3, y=-6. so we can find C from that point. -6=7(3)+C..so we have -6=21+C. C=-6-21=-27

so the equation of the line is y=7x-27

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh