Acharge q of magnitude 6.4 × 10^-19 coulombs moves from point a to point b in an electric field of 6.5 × 10^4 newtons/coulomb. the distance between a and b is 1.2 × 10^-2 meters and the path between a and b is parallel to the field. what is the magnitude of the difference in potential energy?

a. 1.2 × 10^-15 joules
b. 2.3 × 10^-15 joules
c. 3.2 × 10^-15 joules
d. 6.4 × 10^-15 joules
e. 6.4 × 10^-14 joules

In this problem we have the electric field intensity E:

E = 6.5 × newtons/coulomb

We have the magnitude of the load:

q = 6.4 × coulombs

We also have the distance d that the load moved in a direction parallel to the field 1.2 × meters.

We know that the electric potential energy (PE) is:

PE = qEd

So:

PE = (6.4 × )(6.5 × )(1.2 × )

PE = 5.0 x joules

None of the options shown is correct.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.