Atruck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical components of the trucks velocity

a. The horizontal component of the truck's velocity is 5.69 m/s.

b. The vertical component of the truck's velocity is 21.25 m/s.

Given the following data:

To find both the horizontal and vertical components of the truck's velocity:

a. To find the horizontal component of the truck's velocity:

Mathematically, the horizontal component of velocity is given by the formula:

Horizontal component, Vy = 5.69 m/s

b. To find the vertical component of the truck's velocity:

Mathematically, the vertical component of velocity is given by the formula:

Vertical component, Vx = 21.25 m/s

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speed of truck (v) =  22 m/s ,

angle of hill (Θ) =15°

Find

Vertical component (Fv) = ?

Harizontal component (Fh) =?

               Vertical component (Fh) = V cosΘ

                                                        = 22. cos 15

                                                        = 21.25 m/s.

               Harizontal component (Fv) = V sinΘ

                                                            = 22. sin 15

                                                            = 5.69 m/s.

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

unlike poles attract