The resistor has a resistance of 3 ohms. if no change in the battery size occurs, what will happen to the current if the resistance increases to 6 ohms?

Quick answer the current will go down.

The formula is

E = I * R.                 The variation is a direct one. Let us suppose E = 12 volts.

12 = I * 3 ohms        Divide both sides by 3

12/3 = I

I = 4 amps

Now do it again for 6 ohms

12 = I * 6                   Divide both sides by 6

12/6 = I

I = 2

So the current went down from 4 to 2

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

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