Arowboat crosses a river with a velocity of 3.30 mi/h at an angle 62.5â° north of west relative to the water. the river is 0.505 mi wide and carries an eastward current of 1.25 mi/h. how far upstream is the boat when it reaches the opposite shore?

 Rowboat arrives 0.558 miles to the upstream when it reaches the opposite shore.

Explanation:

   Velocity of rowboat = 3.30 mi/h

   Angle with north of west = 62.5⁰

   Width of river = 0.505 mile.

   Velocity of river = 1.25 mi/hr eastward.

Let us take east as positive X -axis and North as positive Y-axis.

   So angle of boat with horizontal axis = (90+62.5) = 152.5⁰

  Horizontal speed of boat = 3.30*cos 152.5 = -2.93 mi/h

  Vertical speed of boat = 3.30*sin 152.5 = 1.52 mi/h

  Horizontal speed of river = 1.25 mi/h

  Time taken to cross river = Width of river/Vertical speed = 0.505/1.52 = 0.33 hour.

  Velocity along upstream of river = -2.93+1.25 = -1.68 mi/hr

  So distance moved along upstream = -1.68*0.33 = -0.558 miles ( negative sign means along west direction)

  It reaches 0.558 miles to the upstream when it reaches the opposite shore.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

the rearrangement of particles in a physical change. hope this