Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. transferring 1.50 ×109 electrons from one disk to the other causes the electric field strength to be 2.00 ×105n/c. what are the diameters of the disks?

The diameter of the disk at the given electrons is 13.1 mm.

The total charge of the capacitor is calculated as follows;

The potential difference between the disk is calculated as follows;

The capacitance of the capacitor is calculated as follows;

The area of the disk is calculated as follows;

The diameter of the disk is calculated as follows;

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The diameter of the disks is 1.32 cm.

If n electrons each of charge e are transferred from one disc to another, calculate the total charge Q transferred from one disc to the other using the expression,

Substitute 1.50×10⁹ for n and 1.6×10⁻¹⁹C for e.

The potential difference V between the disks separated by a distance d is given by,

here, E is the electric field.

Substitute 2.00×10⁵N/C for E and 0.50×10⁻³m for d.

The capacitance C of the capacitor is given by,

The capacitance of a parallel plate capacitor is given by,

Here, ε₀ is the permittivity of free space  and A is the area of the disks.

Rewrite the expression for A.

the area A of the disks is given by,

Here, D is the diameter of the disk.

The diameter of each disc is found to be 1.32 cm.