Aball player catches a ball 3.2 s after throwing it vertically upward. what height did it reach?

At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e  ).

The time of the ball in air is 3.2 s, so ascending time is .

Therefore from kinematic equation,

Substituting the values we get,

, Here v = 0 at top.

Now from equation,

,  here h is the height .

So,

.

Thus, the ball reached at its maximum height of 12.48 m.

where are the vectors ?