This past semester, a professor had a small business calculus section. the students in the class were jinita comma al comma jim comma and william. suppose the professor randomly selects two people to go to the board to work problems. what is the probability that jim is the first person chosen to go to the board and al is the second?

8.3%

Step-by-step explanation:

To solve this question, we will use permutation.

Permutation helps us calculate the number of ways to order items. Basically we multiply the number of elements that can be placed first, then for second place until there is no empty place.

In this case, the probability of selecting Jim first is 1 over the total number of students that is 4. Then:

To select Al in second place is similar, but this time we have 3 students since Jim has already been placed.

Thus, in total the probability will be:

can i get the link to the assignment?

step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option