Which sum contradicts this statement? the sum of two irrational numbers is always irrational. a) 7 + 5 7 b) 4 + 2 9 c) -2 6 + 8 d) -4 6 + 4 6

The correct answer would be Choice D.

I assume you mean to have square root signs in the empty spaces between the numbers.

For choice D, you are adding -4 square roots of 6 and 4 square roots of 6. The answer to that is zero. Which is not an irrational number.

Hey user 

the answer to this is going 

to be 

Choice D.

hope this helps

have a good day

-nick out

21

step-by-step explanation:

21-4