Arug has an area of 48 square feet. two similar rugs have in the areas of 108 square feet in 192 square feet. in each rug, the length is 1 1/3 times the width. which of the following could be the dimensions of the one of the rugs? mark all that apply.

Let
x> the length of a rug
y> the width of a rug

we know that
1 1/3> (1*3+1)/3> 4/3
x=(4/3)*y

case a) area = 48 ft²
48=x*y> 48=(4/3)*y*y> 48=(4/3)*y²> y²=48*3/4
y²=36> y=6 ft
x=(4/3)*6> x=8 ft
The rug dimensions are 8 ft x 6 ft

case b) area = 108 ft²
108=x*y> 108=(4/3)*y*y> 108=(4/3)*y²> y²=108*3/4
y²=81> y=9 ft
x=(4/3)*9> x=12 ft
The rug dimensions are 12 ft x 9 ft

case c) area = 192 ft²
192=x*y> 192=(4/3)*y*y> 192=(4/3)*y²> y²=192*3/4
y²=144> y=12 ft
x=(4/3)*12> x=16 ft
The rug dimensions are 16 ft x 12 ft

The rug dimensions are
 8 ft x 6 ft
12 ft x 9 ft
16 ft x 12 ft

Pick the one(s) that are on your list

This is a robot. try again lol. maybe you attached the wrong image.