Ron has a bag containing 3 green pears and 4 red pears. he randomly selects a pear then randomly selects another pear, without replacement. which tree diagram shows the correct probabilities for this situation?

The third tree diagram is correct.

The probabilities for the first draw are 3/7 for green and 4/7 for red.

If you draw a green pear first, then your probabilities for the second pear would be 2/6 for green and 4/6 for red (since it is done without replacement, the number of pears to choose from changes).

If you draw a red pear first, then your probabilities for the second pear would be 3/6 for green and 3/6 for red.

There are two bc a studen that equals to 2

Xis equal to three