What are the exact solutions of x2 = 4 − 7x? (1 point) x = x equals negative 7 plus or minus the square root of thirty-three all over 2 x = x equals negative 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of thirty-three all over 2?

For this case, the first thing we must do is rewrite the polynomial:
 x ^ 2 + 7x - 4 = 0
 We use the resolver to solve the problem:
 x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
 Where,
 a = 1
 b = 7
 c = -4
 Substituting the values:
 x = (- 7 +/- root ((7) ^ 2 - 4 * (1) * (- 4))) / (2 * (1))
 x = (- 7 +/- root (49 + 16)) / (2 * (1))
 x = (- 7 +/- root (65)) / (2)
 
 x equals negative 7 plus or minus the square root of sixty-five all over 2