Which of the following quadratic equations has the solution set (1/2,5)? select all that apply (x+1/2)(x-5)=0 (x-5)(2x-1)=0 (x+5)(2x-1)=0 (-2x++5)=0 (x+1/2)(x+5)=0 (-2x+1)(x-5)=0

To find the solution set of a factored quadratic equation, you should set each one of the factors equal to zero and solve for .

Lets take our first quadratic equation (x+1/2)(x-5)=0 and apply this. First we are our factors equal to zero  and ; next we are going to sole for  in each factor to find the solution set:
and , so the solution set for the quadratic equation (x+1/2)(x-5)=0 is 

Lets do the same for our next one (x-5)(2x-1)=0


and



So, the solution set for the quadratic equation (x-5)(2x-1)=0 is 

Next one (x+5)(2x-1)=0


and 



So, the solution set for the quadratic equation (x+5)(2x-1)=0 is 

Next one (-2x+1)(-x+5)=0




and



So, the solution set for the quadratic equation (-2x+1)(-x+5)=0 is : therefore, we are going the select this one.

Next one (x+1/2)(x+5)=0


and


So, the solution set for the quadratic equation (x+1/2)(x+5)=0 is 

Finally, our last one (-2x+1)(x-5)=0




and


So, the solution set for the quadratic equation (-2x+1)(x-5)=0 is ; this is also a correct answer, make sure to select this one too.

We can conclude that both (-2x+1)(-x+5)=0 and (-2x+1)(x-5)=0 quadratic equation have  as solution set.

The third box is a function