If 8a + 3b + 2c = 3, what is 64a+24b+16c?

64a+24b+16c = 24

Step-by-step explanation:

Given :  8a + 3b + 2c = 3

We have to find the value of 64a+24b+16c

Consider 64a+24b+16c

Taking 8 common from each term , we have,

64a+24b+16c = 8(8a + 3b + 2c)

Also, given  8a + 3b + 2c = 3

Then , 64a+24b+16c = 8(8a + 3b + 2c)

= 8(3)

Simplify , we have,

= 24

Thus, 64a+24b+16c = 24

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

there are no answer choices

step-by-step explanation: