Mathematics, 27.07.2019 01:00 srsnider2017
If a parametric surface given by r1(u, v)=f(u, v)i+g(u, v)j+h(u, v)k and −2≤u≤2,−3≤v≤3, has surface area equal to 4, what is the surface area of the parametric surface given by r2(u, v)=4r1(u, v) with −2≤u≤2,−3≤v≤3?
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Solve 2x2 + 8 = 0 by graphing the related function. there are two solutions: . there are no real number solutions. there are two solutions: 2 and -2
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Me. i can't figure out this question. give an explanation too. .
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Binh says the point of intersections is (0,-3) which statements identify the errors binh made , check all that apply
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If a parametric surface given by r1(u, v)=f(u, v)i+g(u, v)j+h(u, v)k and −2≤u≤2,−3≤v≤3, has surface...
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