Mathematics, 12.07.2019 16:30 ladybugys
An object is launched at 19.6 m/s from a height of 58.8 m. the equation for the height (h) in terms of time (t) is given by h(t) = -4.9t^2 +19.6t + 58.8. what is the object's maximum height?
Answers: 1
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An object is launched at 19.6 m/s from a height of 58.8 m. the equation for the height (h) in terms...
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