What is the vertex and axis of symmetry of f(x) = (x + 3)(x + 5)?

a vertex (-4, -1) & axis of symmetry x = -1

b vertex (-4, -1) & axis of symmetry x = -4

c vertex (4, 1) & axis of symmetry x = 4

d vertex (-4, 1) & axis of symmetry x = -4

need on this

If you expand y=(x+3)(x+5)
You get: f(x)= x^2+8x+15

A=1 b=8 C=15

To find x-coordinate of vertex:
use formula -b/2a
-8/2(1)= -4 this is x coordinate

To find y coordinate plug the x value in original equation.

F(-4) = (-4+3)(-4+5)
F(-4) = (-1)(1)
F(-4) = -1

Vertex is (-4, -1)

And x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

Axis of symmetry is -4

Option B is answer