Find the asymptotes and intercepts of the function. g(x) = (x-2) / x^2 - 2x - 3

   
 
so, notice, the degree of the numerator is the same degree as the denominator's, therefore the horizontal asymptote is at   

 

the vertical asymptotes are at the zeros of the denominator, let's check.



there are no oblique or slanted asymptotes, that only occurs when the numerator's degree is higher by 1.

to get the x-intercept, simple enough, just set y = 0 and solve for "x" as usual.



and to get the y-intercept, set x = 0, and solve for "y".

Your answer should be “c” mark me brainliest