Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types of observations listed, and determine which order is likely for that reactant. Assume all other factors are held constant. The reaction rate increases in direct proportion to the concentration of the reactant in solution. 1. An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially.
a. first order.
b. second order.
c. zero order.
2. The reaction rate is constant regardless of the amount of reactant in solution.
a. first order.
b. second order.
c. zero order.
3. The reaction rate increases in direct proportion to the concentration of the reactant in solution.
a. first order.
b. second order.
c. zero order.

1) first order

2) zero order

3) second order

Explanation:

For a first order reaction, the concentration of the reactants varies exponentially with the rate of reaction. The curve of a first order reaction shows an exponential relationship between the rate of reaction and the change in the concentration of reactants.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactants. So, regardless of the amount of reactant in solution, the rate of reaction is constant.

For a second reaction, the reaction rate increases in direct proportion to the concentration of the reactant in solution.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j