Write an equation of the line containing the point (3,5)and perpendicular to the line 2x- 3y

The equation of the line would be y = -3/2x + 19/2

Step-by-step explanation:

First we need to solve the original equation for y so that we can find the slope.

2x - 3y = 0

-3y = -2x

y = 2/3x

So since the equation has a slope of 2/3, we know the perpendicular slope would be -3/2 (since perpendicular slopes have opposite and reciprocal slopes). Then we can use this and the ordered pair in point-slope form.

y - y1 = m(x - x1)

y - 5 = -3/2(x - 3)

y - 5 = -3/2x + 9/2

y = -3/2x + 19/2

a. -0.3 > -0.33