The graph of Rx), shown below, has the same shape as the graph of (x) = x2, but it is shifted to the left 1 unit. What is its equation?
5+
F(X) =
O A. F(x) = x2 + 1
O B. Rx) = x2-1
O C. F(X) = (x + 1)2
O D. F(x) = (x - 1)2

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

the answer i believe is 27 units.

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

y=foot

x=foram

a. easy, plug 17 for x and evaluage for y

y=0.860(17)+3.302

y=14.62+3.302

y=17.922 inches

b. rate of change is slope

y=mx+b

m=slope

so

rate or change is 0.860 inches per legnth of forarm

c. what data

d. it is a function

since it is 1st degree (no exponents greater than 1 on the placeholder), and it is not a vertical line

it is a function