Is it possible to have a polygon with an exterior angle of 14 degrees

No, a polygon cannot have a decimal number of sides.

Explanation:

using the formula:

14 = 360 ÷ number of sides

1/number of sides = 14/360

number of sides = 360/14    

number of sides = 25.71428571    

all polygons have exterior angles that totL to 360 degrees from triangles to 20-gons. so 360 divided by 14 is 25.71 sides which is not possible because what would .71 of a side look likenow this is assuming that you were referring to regular polygon with all sides the same. I suppose you could gave a polygon with a whole number of sides but the relationship between the exterior angles could be such that not all of the angles have the same degree measure. I would say that an exterior angle for any polygon would need to be greater than 0 but less than 360. so my answer is yes it could be possible le

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a