The larger of two numbers is 10 less than twice the smaller number. If the sum of the two numbers is 38, find the two numbers.

16,22

larger number=22

smaller number=16

Step-by-step explanation:

let 2x-10=larger number

let x=smaller number

x+2x-10=38

Simplify

3x-10=38

   +10  +10

Add 10 to both sides of the equation

3x=48

divide both sides by 3

x=16

First answer.

2x-10=22

2nd answer

Check your work:

16+22=38

It is correct.

66 & -28

Step-by-step explanation:

x > y

x + y = 38

x = 10 - 2y

10 - 2y + y = 38

-y + 10 = 38

-y = 28

y = -28

x + (-28) = 38

x = 66

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