if the measured diameter of the lowest hole in the front view is 0.200 how far from the ideal location can the axis of the hole be and still be within tolerance?

my answer is$ 12

step-by-step explanation:

because 15 -2=12

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

there is no picture in order for this question to be answered