Q and T are two towns on the same parallel of latitude 50 N. Q is on Longitude 150E and T on Longitude 75 E. Taking the earth as a sphere of radius 6400km and 1 = 3.142. Calculate, correct to three significant figure a)the Radius of the parallel of latitude on which Q and T lie
b) Shorter distance QT measured along the parallel of latitude
c) Distance of T from the equator measure along the line of longitude

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb