Which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle? The triangle is acute because 22 + 52 > 42.
The triangle is acute because 2 + 4 > 5.
The triangle is not acute because 22 + 42 < 52.
The triangle is not acute because 22 < 42 + 52.

The triangle is not acute because 2^2 + 4^2 < 5^2

Step-by-step explanation:

2^2 is side a,

4^2 is side b,

5^2 is side c,

then

c^2 = a^2 + b^2 is right triangle

c^2 > a^2 + b^2 is obtuse

c^2 < a^2 + b^2 is acute

If we insert the numbers into the equation and square them:

c^2 = a^2 + b^2

25 = 4 + 16

25 > 20

This means the triangle is NOT accute, but obtuse

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: